如何将列表从一个函数传递到另一个函数？

Question

问题：玩弄在函数之间交换变量的想法。

我正在执行以下代码：

def benefits():

    list =  ["Beautiful", "Explicit", "Simple", "Readability","Easy to share"]

    return list

def statement(benefit):

    print("The benifit is " + benefit )          

def benefits_of_functions():  

    benefits_list = benefits()

    for benefit in benefits_list:

        print(statement(benefit))

benefits_of_functions()

我得到错误：

The benifit is Beautiful

None

The benifit is Explicit

None

The benifit is Simple

None

The benifit is Readability

None

The benifit is Easy to share

None

我无法理解“无”。你能帮我弄清楚为什么会出现在输出中吗？

Answer 1

在函数中返回而不是打印statement：def benefits():    list =  ["Beautiful", "Explicit", "Simple", "Readability","Easy to share"]    return listdef statement(benefit):    return "The benifit is " + benefitdef benefits_of_functions():      benefits_list = benefits()    for benefit in benefits_list:        print(statement(benefit))benefits_of_functions()