返回包含字母的单词列表

Question

我想返回一个单词列表，其中包含一个不考虑大小写的字母。说如果我有sentence = "Anyone who has never made a mistake has never tried anything new"，那么f(sentence, a)会回来

['Anyone', 'has', 'made', 'a', 'mistake', 'has', 'anything']

这就是我所拥有的

import re 

def f(string, match):

    string_list = string.split()

    match_list = []

    for word in string_list:

        if match in word:

            match_list.append(word)

    return match_list

Answer 1

你不需要re。使用str.casefold：[w for w in sentence.split() if "a" in w.casefold()]输出：['Anyone', 'has', 'made', 'a', 'mistake', 'has', 'anything']

Answer 2

这是另一个变体：sentence = 'Anyone who has never made a mistake has never tried anything new'def f (string, match) :    match_list = []    for word in string.split () :        if match in word.lower ():            match_list.append (word)    return match_listprint (f (sentence, 'a'))

Answer 3

如果没有标点符号，您可以使用字符串拆分。match_list = [s for s in sentence.split(' ') if 'a' in s.lower()]