将格式化为 Pandas DataFrame 的字符串转换为实际的 DataFrame

Question

我正在尝试将格式化的字符串转换为熊猫数据框。

[['CD_012','JM_022','PT_011','CD_012','JM_022','ST_049','MB_021','MB_021','CB_003'

,'FG_031','PC_004'],['NL_003','AM_006','MB_021'],

['JA_012','MB_021','MB_021','MB_021'],['JU_006'],

['FG_002','FG_002','CK_055','ST_049','NM_004','CD_012','OP_002','FG_002','FG_031',

'TG_005','SP_014'],['FG_002','FG_031'],['MD_010'],

['JA_012','MB_021','NL_003','MZ_020','MB_021'],['MB_021'],['PC_004'],

['MB_021','MB_021'],['AM_006','NM_004','TB_006','MB_021']]

我正在尝试使用该pandas.DataFrame方法来执行此操作，但结果是整个字符串都放置在DataFrame.

Answer 1

最好的方法是用 '],[' 分隔符分割字符串，然后转换为 df。import numpy as npimport pandas as pddef stringToDF(s):    array = s.split('],[')    # Adjust the constructor parameters based on your string    df = pd.DataFrame(data=array,                  #index=array[1:,0],                 #columns=array[0,1:]             )     print(df)    return dfstringToDF(s)祝你好运！

Answer 2

你是这个意思吗？import pandas as pdlist_of_lists = [['CD_012','JM_022','PT_011','CD_012','JM_022','ST_049','MB_021','MB_021','CB_003'                ,'FG_031','PC_004'],['NL_003','AM_006','MB_021'],                ['JA_012','MB_021','MB_021','MB_021'],['JU_006'],                ['FG_002','FG_002','CK_055','ST_049','NM_004','CD_012','OP_002','FG_002','FG_031',                'TG_005','SP_014'],['FG_002','FG_031'],['MD_010'],                ['JA_012','MB_021','NL_003','MZ_020','MB_021'],['MB_021'],['PC_004'],                ['MB_021','MB_021'],['AM_006','NM_004','TB_006','MB_021']]result = pd.DataFrame({'result': list_of_lists})