我正在对不同的 URL 进行并发 GET 请求(在本例中为 1000)。对于这些要求,我遵循了消费者-生产者设计。有 50 个工人(goroutines - 爬虫)和 1 个生产者(用 url 填充频道)。
问题:我已将客户端中的超时设置为 15 秒(我不想等待每个请求超过 15 秒)。但是当一个 URL 使 goroutine 等待超过 15 秒时,我的代码退出
超出上下文期限(Client.Timeout 或阅读正文时取消上下文)
想要的行为:当服务器花费超过 15 秒时,我希望相关的 goroutine 简单地继续下一个 URL
这是代码片段:
package main
import (
"bufio"
"fmt"
"io"
"log"
"net/http"
"os"
"sync"
"time"
)
func crawler(wg *sync.WaitGroup, urlChannel <-chan string) {
defer wg.Done()
client := &http.Client{Timeout: 15 * time.Second} // single client is sufficient for multiple requests
for urlItem := range urlChannel {
req1, _ := http.NewRequest("GET", "http://"+urlItem, nil) // generating the request
req1.Header.Add("User-agent", "Mozilla/5.0 (X11; Linux i586; rv:31.0) Gecko/20100101 Firefox/74.0") // changing user-agent
resp1, respErr1 := client.Do(req1) // sending the prepared request and getting the response
if respErr1 != nil {
fmt.Println("server error", urlItem)
continue
}
if resp1.StatusCode/100 == 2 { // means server responded with 2xx code
f1, fileErr1 := os.Create("200/" + urlItem + "_original.txt") // creating the relative file
if fileErr1 != nil {
fmt.Println("file error", urlItem)
log.Fatal(fileErr1)
}
_, writeErr1 := io.Copy(f1, resp1.Body) // writing the sourcecode into our file
if writeErr1 != nil {
fmt.Println("file error", urlItem)
log.Fatal(writeErr1)
}
f1.Close()
resp1.Body.Close()
fmt.Println("success:", urlItem)
}
}
}
如何实现想要的行为(如果达到超时,则跳过 URL)?
智慧大石
相关分类