按下设备上的后退按钮时,如何防止应用程序最小化/退出?
在我的设备上按下返回按钮时,我试图分配“浏览器返回”功能,这是我的代码:
import 'react-native-get-random-values';
import React, { useState, useRef, Component, useEffect } from 'react'
import {
Alert,
SafeAreaView,
StyleSheet,
StatusBar,
View,
Text,
ScrollView,
BackHandler,
RefreshControl
} from 'react-native'
import WebView from 'react-native-webview'
import Icon from 'react-native-vector-icons/FontAwesome';
import { Button } from 'react-native-elements';
const App = () => {
function backButtonHandler(){}
function refreshHandler(){
if (webviewRef.current) webviewRef.current.reload()
}
useEffect(() => {
BackHandler.addEventListener("hardwareBackPress", backButtonHandler);
return () => {
BackHandler.removeEventListener("hardwareBackPress", backButtonHandler);
};
}, [backButtonHandler]);
let jscode = `window.onscroll=function(){window.ReactNativeWebView.postMessage(document.documentElement.scrollTop||document.body.scrollTop)}`;
const [canGoBack, setCanGoBack] = useState(false)
const [currentUrl, setCurrentUrl] = useState('')
const [refreshing, setRefreshing] = useState(false);
const [scrollviewState, setEnableRefresh] = useState(false);
const webviewRef = useRef(null)
const scrollviewRef = useRef(false)
backButtonHandler = () => {
if (webviewRef.current) webviewRef.current.goBack()
}
我的问题是当我按下设备上的后退按钮时,它确实调用了backButtonHandler函数并且我的 webview 导航回来,但同时应用程序也最小化了..有没有办法防止这种情况?
慕斯709654
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