while循环如何显示循环运行次数

Question

只要满足条件 sumaA > sumaB，我就想运行“while”循环。如何显示 sumaA 和 sumaB 的迭代次数和当前值？

import java.util.*;

class Sum {

    public static void main(String[] args) {

        int sumaA = 1000;

        int sumaB = 0;

        Random rand = new Random();

        int n = rand.nextInt(9);

        int g = rand.nextInt(49);{

            System.out.println("Random N= "+ n);

            sumaA += n;

            System.out.println("sumaA: "+sumaA);

            System.out.println();

            System.out.println("Random N= "+ g);

            sumaB += g;

            System.out.println("sumaB: "+sumaB);

            while (sumaA>sumaB);

            }

        System.out.println("loop runs numbers");

        System.out.println("value sumaA" + sumaA + "value sumaB " + sumaB);

        }

    }

Answer 1

你必须纠正你的while循环，因为在它的当前状态下，它不会做任何事情。这是对您的代码的更正，它基本上可以工作（我不知道所需的输出，但看起来不错）：public static void main(String[] args) {    int sumaA = 1000;    int sumaB = 0;    Random rand = new Random();    int n = rand.nextInt(9);    int g = rand.nextInt(49);    int runCounter = 0;    while (sumaA > sumaB) {        runCounter++;        System.out.println("Loop run number " + runCounter);        System.out.println("Random N = " + n);        sumaA += n;        System.out.println("sumaA: " + sumaA);        System.out.println();        System.out.println("Random N= " + g);        sumaB += g;        System.out.println("sumaB: " + sumaB);    }    System.out.println("loop ran " + runCounter + " times");    System.out.println("value sumaA" + sumaA + "value sumaB " + sumaB);}请看一下循环现在的样子。每次循环运行要执行一次的所有内容都必须在循环主体内（大括号）。

Answer 2

  do {      int n = rand.nextInt(9);    int g = rand.nextInt(49);        System.out.println("Random N= "+ n);        sumaA += n;        System.out.println("sumaA: "+sumaA);        System.out.println();        System.out.println("Random N= "+ g);        sumaB += g;        System.out.println("sumaB: "+sumaB);        System.out.println("loop runs numbers");        System.out.println("value sumaA" + sumaA + "value sumaB " + sumaB);        }  while (sumaA>sumaB);    }你好，这是你想做的吗？

Answer 3

您必须正确构造您的 while 循环并获取局部变量 counter 并将其初始化为 0。而 while 迭代在 counter 变量中添加 +1。请考虑以下代码：public static void main( String[] args )   {      int sumaA = 1000;      int sumaB = 0;      int counter = 0;      Random rand = new Random();      int n = rand.nextInt( 9 );      int g = rand.nextInt( 49 );      while ( sumaA > sumaB )      {         System.out.println( "Random N= " + n );         sumaA += n;         System.out.println( "sumaA: " + sumaA );         System.out.println();         System.out.println( "Random N= " + g );         sumaB += g;         System.out.println( "sumaB: " + sumaB );         counter++;      }      System.out.println( "loop runs numbers " + counter );      System.out.println( "value sumaA " + sumaA + "value sumaB " + sumaB );   }

Answer 4

while 循环括号内的代码，直到括号内的条件为假。因此，例如这段代码：int i = 0;loops = 0while(i < 6){&nbsp; loops++;&nbsp; System.out.println("loop runs numbers"+loops);&nbsp; i+=2;&nbsp; System.out.println("i: "+i);}输出：循环运行数字 1我：2循环运行数字 2我：4循环运行数字 3我：6然后因为 i 不小于 6 而停止。现在您的代码的问题是您的 while 括号内没有任何指令，因此括号内的条件以 true 开始，并且永远不会变为 false，因为您没有在循环内更改任何内容。您应该做的是将代码移动到 while 括号内，如果您希望计算循环运行次数，请添加一个“循环”变量。最终代码应如下所示：import java.util.*;class Sum {&nbsp; &nbsp; public static void main(String[] args) {&nbsp; &nbsp; int sumaA = 1000;&nbsp; &nbsp; int sumaB = 0;&nbsp; &nbsp; int loops = 0;&nbsp; &nbsp; while (sumaA>sumaB){&nbsp; &nbsp; &nbsp; Random rand = new Random();&nbsp; &nbsp; &nbsp; int n = rand.nextInt(9);&nbsp; &nbsp; &nbsp; int g = rand.nextInt(49);{&nbsp; &nbsp; &nbsp; System.out.println("Random N= "+ n);&nbsp; &nbsp; &nbsp; sumaA += n;&nbsp; &nbsp; &nbsp; System.out.println("sumaA: "+sumaA);&nbsp; &nbsp; &nbsp; System.out.println();&nbsp; &nbsp; &nbsp; System.out.println("Random N= "+ g);&nbsp; &nbsp; &nbsp; sumaB += g;&nbsp; &nbsp; &nbsp; System.out.println("sumaB: "+sumaB);&nbsp; &nbsp; &nbsp; loops++;&nbsp; &nbsp; &nbsp; System.out.println("loop runs numbers"+loops);&nbsp; &nbsp; &nbsp; System.out.println("value sumaA" + sumaA + "value sumaB " + sumaB);&nbsp; &nbsp; }&nbsp; }}