循环更改井字游戏矩阵中的值？

Question

我正在制作一个井字游戏，并且我确实有工作代码，并且到目前为止它可以完成我想要它做的事情。我只是想知道是否有办法缩短这个功能。我的代码如下...

def EnterMove(board):

    move = input("Enter your move (number between 1 - 9): ")

    if move == '1':

        board[0][0] = 'O'

    elif move == '2':

        board[0][1] = 'O'

    elif move == '3':

        board[0][2] = 'O'

    elif move == '4':

        board[1][0] = 'O'

    elif move == '5':

        board[1][1] = 'O'

    elif move == '6':

        board[1][2] = 'O'

    elif move == '7':

        board[2][0] = 'O'

    elif move == '8':

        board[2][1] = 'O'

    elif move == '9':

        board[2][2] = 'O'

#Making the playing board

board = []

for i in range(3):

    row = [Empty for i in range(3)]

    board.append(row)

board[0][0] = '1'

board[0][1] = '2'

board[0][2] = '3'

board[1][0] = '4'

board[1][1] = '5'

board[1][2] = '6'

board[2][0] = '7'

board[2][1] = '8'

board[2][2] = '9'

所以就像我说的那样，到目前为止，这一切都很好，我只是想知道是否有更简单的方法来构建板和构建 EnterMove 功能。非常感谢。

（注意：玩家移动将是“O”，而计算机将是“X”，我将向我们提供与玩家移动功能几乎相同的代码，但只是使用str(random.randint(1,9))它来决定计算机的移动)

Answer 1

您可以使用除法和取模来获取行和列：def EnterMove(board):    move = int(input("Enter your move (number between 1 - 9): ")) - 1    board[move // 3][move % 3] = 'O'board = []for i in range(3):    row = [Empty for i in range(3)]    board.append(row)for i in range(9):    board[i // 3][i % 3] = str(i + 1)