如何在 php 和 twig 中渲染视图？

Question

我正在创建一个网页，学生和教师可以在其中登录，教师创建关卡，学生可以完成该关卡。

我解释一下，我正在使用 php 和 twig，我想渲染一个在函数中传递参数的视图。我创建了一个名为 Professors 的 budle，其中有目录 Controllers、Models 和 Templates。

在模板中，我有professionals.html，我在其中显示一些信息和一个按钮来为学生创建关卡，我还有crearNivell.html，老师可以在其中创建关卡。当我在页面浏览教授中时，我的 URL 是这个：

当我单击“创建级别”按钮时，我希望我的 URL 如下所示：

相反，我得到了这个 URL，这个 URL 返回了一个错误。

在Controllers/ProfessorsController.php我有那个代码：

class ProfessorController extends Controller{

public function process($params)

{

    /*var_dump($params);

    die();*/

    if(empty($params[0])){

        $this->getProfessor(); //Here I return the view professor

    }elseif(isset($params[0]) && $params[0] == "crearNivell"){

        $this->twig = "crearNivell.html";

    }

}

public function getProfessor(){

    $this->twig = "professor.html";

}

}

有人可以帮我写代码吗？

Answer 1

几天前我找到了问题的答案。我把自己复杂化了，就像这样：首先，您在 Templates 文件夹中创建视图。$params 引用 URL。例如：校友是捆绑AlumneController.php然后在 AlumneController.php 中输入不带 .html 的视图名称，然后使用$this->twig = "name_Of_The_View.html";<?php&nbsp;class AlumneController extends Controller{&nbsp; &nbsp; public function process($params)&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; /*var_dump($params);&nbsp; &nbsp; &nbsp; &nbsp; die();*/&nbsp; &nbsp; &nbsp; &nbsp; if(empty($params[0])){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; $this->getAlumne();&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; /*echo $usuari = $_SESSION["username"];*/&nbsp; &nbsp; &nbsp; &nbsp; }else if(isset($params[0]) && $params[0] == "instruccions"){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; $this->twig = "instruccions.html";&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; /*echo $usuari = $_SESSION["username"];*/&nbsp; &nbsp; &nbsp; &nbsp; }else if(isset($params[0]) && $params[0] == "resultats"){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; $this->twig = "resultats.html";&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; /*echo $usuari = $_SESSION["username"];*/&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }&nbsp; &nbsp; public function getAlumne(){&nbsp; &nbsp; &nbsp; &nbsp; $this->twig = "alumne.html";&nbsp; &nbsp; }&nbsp;}校友.html在按钮或链接中，您用于访问您在其中写入路径的页面<a href="bundle/view_name">Instruccions</a><a class="mdl-navigation__link" href="alumne/instruccions">Instruccions</a><a class="mdl-navigation__link" href="alumne/resultats">Resultats</a>AlumneController.php然后在 AlumneController.php 中输入不带 .html 的视图名称，然后使用$this->twig = "name_Of_The_View.html";<?php&nbsp;class AlumneController extends Controller{&nbsp; &nbsp; public function process($params)&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; /*var_dump($params);&nbsp; &nbsp; &nbsp; &nbsp; die();*/&nbsp; &nbsp; &nbsp; &nbsp; if(empty($params[0])){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; $this->getAlumne();&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; /*echo $usuari = $_SESSION["username"];*/&nbsp; &nbsp; &nbsp; &nbsp; }else if(isset($params[0]) && $params[0] == "instruccions"){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; $this->twig = "instruccions.html";&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; /*echo $usuari = $_SESSION["username"];*/&nbsp; &nbsp; &nbsp; &nbsp; }else if(isset($params[0]) && $params[0] == "resultats"){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; $this->twig = "resultats.html";&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; /*echo $usuari = $_SESSION["username"];*/&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }&nbsp; &nbsp; public function getAlumne(){&nbsp; &nbsp; &nbsp; &nbsp; $this->twig = "alumne.html";&nbsp; &nbsp; }&nbsp;}校友.html在按钮或链接中，您用于访问您在其中写入路径的页面<a href="bundle/view_name">Instruccions</a><a class="mdl-navigation__link" href="alumne/instruccions">Instruccions</a><a class="mdl-navigation__link" href="alumne/resultats">Resultats</a>

Answer 2

我认为您正在寻找的是Twig 的 API。更具体地说，您需要下面的行来渲染模板，并在数组中传递一些参数：echo&nbsp;$template->render(['the'&nbsp;=>&nbsp;'variables',&nbsp;'go'&nbsp;=>&nbsp;'here']);如果您使用 PHP 将某些内容“打印”到浏览器的最快方式是echo，请不要犹豫使用它。