我应该将请求对象传递给 goroutine 以阻止来自通道的 for-select 循环吗？

Question

我在代码中有以下 for-select 结构：

go func(runCh chan Caller, shutdownSignal chan bool) {

        for {

            select {

            case request := <-runCh:

                go func() {

                    w.Run(&request)

                }()

            case <-shutdownSignal:

                w.Shutdown()

                return

            }

        }

    }(runCh, shutdownCh)

这部分我会有一些问题吗：

case request := <-runCh:

    go func() {

        w.Run(&request)

    }()

?

如果是，那为什么？

换句话说 -常见错误的循环迭代器变量部分使用 goroutines 是否也适用于我的案例，为什么它在这里适用/不适用？

Answer 1

不（不适用于此处），每次循环迭代都有新变量（内存地址）：&nbsp;case request := <-runCh:因为这:=会创建与前一个不同的新变量，所以证明：package mainimport (&nbsp; &nbsp; "fmt"&nbsp; &nbsp; "time")func main() {&nbsp; &nbsp; runCh := make(chan int, 2)&nbsp; &nbsp; runCh <- 1&nbsp; &nbsp; runCh <- 2&nbsp; &nbsp; for i := 1; i <= 2; i++ {&nbsp; &nbsp; &nbsp; &nbsp; select {&nbsp; &nbsp; &nbsp; &nbsp; case request := <-runCh:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; go func() {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; fmt.Println(request, &request)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; time.Sleep(200 * time.Millisecond)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; fmt.Println(request, &request)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }()&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }&nbsp; &nbsp; time.Sleep(500 * time.Millisecond)}输出（request每次循环迭代中的地址不同）：1 0xc0000b80002 0xc0000b80081 0xc0000b80002 0xc0000b8008请参阅：0xc0000b8000 ！= 0xc0000b8008