python如何解析指定div标签中的标签

Question

我已经尝试了这个网站上的其他解决方案，但仍然无法解决问题，我的问题是：

<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt

我想解析这个“ds”类中的所有 div 标题，谢谢你的帮助

Answer 1

使用BeautifulSoup,lxml或类似模块代替regex.美丽汤：from bs4 import BeautifulSouptext = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'soup = BeautifulSoup(text, 'html.parser')for item in soup.select('.ds div[title]'):&nbsp; &nbsp; print(item['title'])# or as list comprehensions&nbsp; &nbsp;&nbsp;titles = [item['title'] for item in soup.select('.ds div[title]')]print(titles)lxml：import lxml.htmltext = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'soup = lxml.html.fromstring(text)for item in soup.cssselect('.ds div[title]'):&nbsp; &nbsp; print(item.attrib['title'])# or as list comprehensions&nbsp; &nbsp;&nbsp;titles = [item.attrib['title'] for item in soup.cssselect('.ds div[title]')]print(titles)查询：import pyquerytext = '<div class="ds"><div title="Today" class="dh">...<div title="Pazartesi" class="dh">26 Agu Pzt'soup = pyquery.PyQuery(text)for item in soup('.ds div[title]'):&nbsp; &nbsp; print(item.attrib['title'])# or as list comprehensions&nbsp; &nbsp;&nbsp;titles = [item.attrib['title'] for item in soup('.ds div[title]')]print(titles)parsel : (由Scrapy 的 Selectors使用)import parselsel = parsel.Selector(text)for item in sel.css('.ds div[title]'):&nbsp; &nbsp; print(item.attrib['title'])titles = [item.attrib['title'] for item in sel.css('.ds div[title]')]print(titles)