如何在不运行以下脚本的情况下退出循环

Question

我想从第二个循环跳到第一个循环（比如休息），但休息后我不想打印fmt.Println("The value of i is", i)。算法如何？

package main

import "fmt"

func main() {

    for i := 0; i < 2; i++ {

        for j := 0; j < 4; j++ {

            if j == 2 {

                fmt.Println("Breaking out of loop")

                break

            } else {

                fmt.Println("j = ", j)

            }

        }

        fmt.Println("The value of i is", i)

    }

}

Answer 1

编辑：你编辑了你的代码，所以这里是编辑后的答案。要从内部继续外循环（打破内循环并跳过外循环的其余部分），您必须继续外循环。要使用语句解决外部循环，请continue使用标签：outer:&nbsp; &nbsp; for i := 0; i < 2; i++ {&nbsp; &nbsp; &nbsp; &nbsp; for j := 0; j < 4; j++ {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; if j == 2 {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; fmt.Println("Breaking out of loop")&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; continue outer&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; } else {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; fmt.Println("j = ", j)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; fmt.Println("The value of i is", i)&nbsp; &nbsp; }这将输出（在Go Playground上尝试）：j =&nbsp; 0j =&nbsp; 1Breaking out of loopj =&nbsp; 0j =&nbsp; 1Breaking out of loop原答案：break总是从最内层循环中断（更具体地说是 a或） for，因此之后外层循环将继续其下一次迭代。switchselect如果您有嵌套循环，并且您想从外部循环中断内部循环，则必须使用标签：outer:&nbsp; &nbsp; for i := 0; i < 2; i++ {&nbsp; &nbsp; &nbsp; &nbsp; for j := 0; j < 4; j++ {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; if j == 2 {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; fmt.Println("Breaking out of loop")&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; break outer&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; fmt.Println("The value of j is", j)&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }这将输出（在Go Playground上尝试）：The value of j is 0The value of j is 1Breaking out of loop