我有一个对话框,当前在单击按钮时打开并且工作正常,但这意味着我有一个看起来不太好看的丑陋按钮,我希望它从CardView.
这是卡片视图:
CardView manager=findViewById(R.id.manager_card);
manager.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {}
});
这是当前通过单击按钮打开的对话框:
Button btnLoginDialog;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_sign_in);
// Init Widget Button and set click listener
btnLoginDialog = (Button) findViewById(R.id.btnLoginDialog);
btnLoginDialog.setOnClickListener(this);
}
@Override
public void onClick(View v) {
if (v == btnLoginDialog) {
// Create Object of Dialog class
final Dialog login = new Dialog(this);
// Set GUI of login screen
login.setContentView(R.layout.login_gui);
login.setTitle("Login to Pulse 7");
// Init button of login GUI
Button btnLogin = (Button) login.findViewById(R.id.btnLogin);
Button btnCancel = (Button) login.findViewById(R.id.btnCancel);
final EditText txtUsername = (EditText)login.findViewById(R.id.txtUsername);
final EditText txtPassword = (EditText)login.findViewById(R.id.txtPassword);
// Attached listener for login GUI button
btnLogin.setOnClickListener(new OnClickListener() {
我想不通。我希望那里有足够的信息可以帮助我。
jeck猫
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