Python ReportLab 段落计数打印行数

Question

有什么方法可以让我在 reportlab 中获得 Flowable Paragraph 的行数？我有一个用不同大小和字体打印的很长的字符串。我需要知道使用 TA_JUSTIFY 对齐方式打印的整个段落使用了多少行。

这能做到吗？

下面是我的示例 python 文件

import os

import sys

import string

import pprint

import imp

import tempfile

from reportlab.pdfgen import canvas

from reportlab.platypus import Preformatted, XPreformatted, Paragraph, Frame, Image, \

     Table, TableStyle, Spacer

from reportlab.lib.enums import TA_LEFT, TA_RIGHT, TA_CENTER, TA_JUSTIFY

from reportlab.lib import styles

from reportlab.lib.styles import getSampleStyleSheet, ParagraphStyle

from reportlab.lib.pagesizes import *

from reportlab.lib import colors

import reportlab.rl_config

# Import as may be needed if we require embedded true type fonts

from reportlab.pdfbase import pdfmetrics

from reportlab.pdfbase.ttfonts import TTFont

from reportlab.lib.fonts import addMapping

from reportlab.graphics.barcode import code39, code128, code93

from reportlab.graphics.barcode import common

from reportlab.graphics.barcode import qr

from reportlab.graphics import renderPDF

from reportlab.graphics.shapes import Drawing

import string

import os

import imp

from reportlab.lib import colors

canv = canvas.Canvas('Output.pdf')

styles = getSampleStyleSheet()

parastyle = ParagraphStyle(name='Justify', alignment=TA_JUSTIFY)

parastyle.leading = 12

parastyle.fontSize = 11

styles.add(parastyle)

我需要获取段落中打印的行数。在我的例子中，我必须得到 11。

如果我更改字体和字体大小，我必须相应地获取值。

Answer 1

在你调用Paragraph.wrapor 之后Paragraph.wrapOn，你有一个叫做blParaavailable的属性，它有一个叫做lines列表的属性。你可以使用它的长度。像这样：from reportlab.lib.enums import TA_JUSTIFYfrom reportlab.lib.pagesizes import A4from reportlab.lib.styles import ParagraphStylefrom reportlab.lib.units import mmfrom reportlab.pdfgen.canvas import Canvasfrom reportlab.platypus import Paragraphcanvas = Canvas("test.pdf")drawText = "The Avengers become divided, both over how to approach Loki and the revelation that S.H.I.E.L.D. plans to harness the Tesseract to develop weapons as a deterrent against hostile extraterrestrials. As the group argues, Barton and Loki's other possessed agents attack the Helicarrier, disabling one of its engines in flight and causing Banner to transform into the Hulk. Stark and Rogers work to restart the damaged engine, and Thor attempts to stop the Hulk's rampage. Romanoff reluctantly fights Barton, and knocks him unconscious, breaking Loki's mind control. Loki escapes after killing Coulson and ejecting Thor from the airship, while the Hulk falls to the ground after attacking a S.H.I.E.L.D. fighter jet. Fury uses Coulson's death to motivate the Avengers into working as a team. Stark and Rogers realize that for Loki, simply defeating them will not be enough; he needs to overpower them publicly to validate himself as ruler of Earth. Loki uses the Tesseract, in conjunction with a device Selvig built, to open a wormhole above Stark Tower to the Chitauri fleet in space, launching his invasion."availWidth, availHeight = 190*mm, A4[1]style = ParagraphStyle("justifies", alignment=TA_JUSTIFY, fontSize=11, leading=12)par = Paragraph(drawText, style=style)par.wrap(availWidth, availHeight)par.drawOn(canvas, 10*mm, A4[1]-10*mm-par.height)print(len(par.blPara.lines))  # 11canvas.save()还有simpleSplit它做同样的工作，额外的好处是更容易获得每一行的文本。from reportlab.lib.utils import simpleSplitlines = simpleSplit(drawText, style.fontName, style.fontSize, availWidth)

Answer 2

我刚刚遇到了这个问题，同时也在寻找一些简单的方法来完成您的要求。不幸的是我没有找到答案，所以我试图把一些东西放在一起来让它工作。它不漂亮，但它有效！我刚刚在您的 canv.save() 方法调用之后添加了此代码：pixelRatio = 1.333333 # 1 point = 1.333333 pixels# https://websemantics.uk/articles/font-size-conversion/# http://www.endmemo.com/sconvert/pixelpoint.php#targetText=Pixel%E2%86%94Point%201%20Point,Twip%201%20Pixel%20%3D%2015%20TwipfontLineHeight = styles["Justify"].fontSize * pixelRatioboxWidth = widthboxHeight = heightboxLines = int(72/fontLineHeight)boxLRBuffer = 0 # Adjust this to whatever inside margin/padding you have in your boxboxPixelCapacity = boxWidth * boxLines - boxLRBuffer # Total pixels in the box# A list to hold the lines of texttextLines = []# A pointer to indicate which character is being evaluatedposition = len(drawText)# Make a copy of the original string so as to not modify ittempString = drawText# This is a dummy string used to test the width of the stringtestString1 = tempString# Another dummy string to hold what is not being split into a line# testString2 will be build going backwards from the last character# to the character right after the line splittestString2 = ''# Boolean flag to get out of the while loopdone = Falsewhile not done:    # Use pdfmetrics to get the line width in points based upon the fontName and fontSize used    if pdfmetrics.stringWidth(testString1, styles["Justify"].fontName, styles["Justify"].fontSize, 'utf8') > boxWidth-boxLRBuffer*2:        # Since the line is too long, move backwards through the string until an appropriate size is found        # by decreasing the pointer position.  Spaces also take space.        position -= 1        if position >= 0:            #since the the pointer has not reached the beginning of testString1            testString1 = testString1[:position] # remove the last character from testString1            testString2 = tempString[position:] # add the next character to testString2 for later use    # Since testString1 now fits within the stringWidth    # it must be checked to see if this is the last line    # being processed.    elif testString1 == testString2:        # This must be the last line since it equals testString2            textLines.append(testString2.strip())            break    # This is not the last line of text, so now work backwards in    # the string to find a space so the line can be split    elif ' ' in testString1:        while testString1[position:] != ' ' and position >= 0:            testString1 = testString1[:position]            testString2 = tempString[position:]            position -= 1        if len(testString1):            textLines.append(testString1.strip())        else:            textLines.append(testString2.strip())            break        tempString = tempString[position:].strip()        testString1 = tempString        position = len(tempString)    elif testString1 == "":        # It's done        break    else:        # The text does not exceed the stringWidth        textLines.append(testString1)        # testString2 must be checked and if empty then it's done        if testString2 == "":            done = True        else:           tempString = tempString[position:].strip()           testString1 = tempString           position = len(tempString)print(len(textLines))我愿意接受使此代码更好或更精简的建议。