Python 函数不会退出或指向另一个函数

Question

正在做我的 Python 评估，除了不断地展示自己之外，我无法让我的功能做任何事情。它不会退出或转移到下一个功能对不起，如果这有点傻，但我真的不知道该怎么做或如何描述问题

    def main_menu():          

    menu_choice = input("""

---------------------------------------

Welcome to the GCSE Celebrity Dogs Game

 Please choose an option from the menu

---------------------------------------

1) Play the game

2) Quit

""")

    if menu_choice == 1:

     deck_choice()

    elif menu_choice == 2:

     print("Exiting game.....")

     quit()

    else:

     main_menu()

correct_numbers = [6,8,10,12,14,16,18,20,22,24,26,28,30]

def deck_choice():

    num_cards = input("""

How many cards owuld you liek to play with?

**Please note this must be a number between 4 and 30 and cannot be odd**

""")

    if num_cards not in correct_numbers:

        print("Sorry, that number isnt valid. Please enter another number")

    else:

        return num_cards

main_menu() 

Answer 1

您需要将 to 转换为menu_choicetoint以便您可以将其与 an 进行比较，int或者将 int 转换为if语句中的字符串。例如，要将输入转换为 int：menu_choice = input("""your menu""")if int(menu_choice) == 1:    # do stuff或者，将 int 转换为字符串：menu_choice = input("""your menu""")if menu_choice == str(1):    # do stuff