如何在 Go 中传递嵌套结构

Question

一个小的 2 文件应用程序，它读取配置文件并将其存储在struct. 如何将部分配置struct传递给fetchTemperature函数？

配置

package configuration

type Config struct {

    Temperatures []struct {

        Temperature

    }

}

type Temperature struct {

    AppId string

}

func Load() Config {

    var c Config

    // -- 8< -- snip -- 8< --

    return c

}

主要的

package main

import "configuration"

var c configuration.Config = configuration.Load()

func main() {

    for _, t := range c.Temperatures {

        fetchTemperature(t)

    }

}

func fetchTemperature(t configuration.Temperature) {

    // -- 8< -- snip -- 8< --

}

给我：

cannot use t (type struct { configuration.Temperature }) as type configuration.Temperature in argument to fetchTemperature

不是t，configuration.Temperature如果不是，我该如何struct绕过？

Answer 1

type Config struct {&nbsp; &nbsp; Temperatures []struct {&nbsp; &nbsp; &nbsp; &nbsp; Temperature&nbsp; &nbsp; }}t是Config.Temperatures[i]。对于Temperaturefrom anonymous struct { Temperature }，写入t.Temperature以从结构中选择字段。例如，package mainimport "configuration"var c configuration.Config = configuration.Load()func main() {&nbsp; &nbsp; for _, t := range c.Temperatures {&nbsp; &nbsp; &nbsp; &nbsp; fetchTemperature(t.Temperature)&nbsp; &nbsp; }}func fetchTemperature(t configuration.Temperature) {&nbsp; &nbsp; //&nbsp; -- 8< -- snip -- 8< --}我怀疑你的困惑是因为你写的type Config struct {&nbsp; &nbsp; Temperatures []struct {&nbsp; &nbsp; &nbsp; &nbsp; Temperature&nbsp; &nbsp; }}Temperatures是一个匿名类型的切片struct { configuration.Temperature }。你可能想要的是type Config struct {&nbsp; &nbsp; Temperatures []Temperature}Temperatures是一个类型的切片configuration.Temperature。