Puppeteer 从 Node 中监听 map.on('load')

Question

使用 Puppeteer 从 Node 中监听 map.on('load')。

(async () => {

  const browser = await puppeteer.launch({ headless: false, devtools: true });

  const page = await browser.newPage();

  function nodeLog(msg) {

    console.log(msg);

  }

  page.on('load', async () => {

    await page.evaluate(() => {

      window.map.on('load', () => {

        console.log("This runs on the index.html js but I do not need that");

        nodeLog("WHY IS THIS NOT WORKING??")

      })

    })

  });

  await page.goto(`file:${__dirname + '/index.html'}`);

})();

Answer 1

我还想出了如何返回信息。我重读了文档并得到了一些理解。我不理解上下文。const nodeLog = msg => console.log;const msg = await page.evaluate(() => { return 'this is working' });nodeLog(msg);