C# Xamarin iOS RegisteredForRemoteNotifications

Question

你好 ！

我正在尝试使用Azure Notification Hub在我的 xamarin iOS 应用程序上添加通知。

按照本教程（https://docs.microsoft.com/en-us/azure/notification-hubs/xamarin-notification-hubs-ios-push-notification-apns-get-started）之后，我遇到了一个问题在我的 appdelegate.cs 文件中：RegisteredForRemoteNotifications方法从未被触发，因此我的应用程序无法在我的集线器上注册。

通知的所有权限都已完成，设置也是如此，我做了很多研究，但没有一个解决方案适用于我的情况。我已经尝试过Xamarin.iOS RegisteredForRemoteNotifications not called

在我的 FinishedLaunching 方法中，我有：

if (UIDevice.CurrentDevice.CheckSystemVersion(10, 0))

{

        UNUserNotificationCenter.Current.RequestAuthorization(UNAuthorizationOptions.Alert | UNAuthorizationOptions.Badge | UNAuthorizationOptions.Sound, (granted, error) => 

        {

            if (granted)

            {

                    InvokeOnMainThread(UIApplication.SharedApplication.RegisterForRemoteNotifications);

            }

        });

}

else if (UIDevice.CurrentDevice.CheckSystemVersion(8, 0))

{

        var pushSettings = UIUserNotificationSettings.GetSettingsForTypes(UIUserNotificationType.Alert | UIUserNotificationType.Badge | UIUserNotificationType.Sound, new NSSet());

        UIApplication.SharedApplication.RegisterUserNotificationSettings(pushSettings);

        UIApplication.SharedApplication.RegisterForRemoteNotifications();

}

else

{

        UIRemoteNotificationType notificationTypes = UIRemoteNotificationType.Alert | UIRemoteNotificationType.Badge | UIRemoteNotificationType.Sound;

        UIApplication.SharedApplication.RegisterForRemoteNotificationTypes(notificationTypes);

}

我的RegisteredForRemoteNotifications方法是：

public override void RegisteredForRemoteNotifications(UIApplication application, NSData deviceToken)

    {

            Hub = new SBNotificationHub(Constants.ListenConnectionString, Constants.NotificationHubPath);

            Hub.UnregisterAllAsync(deviceToken, (error) => {

                if (error != null)

                {

                        Console.WriteLine("Error calling Unregister: {0}", error.ToString());

                        return;

                }