如何随机化一个字符的值？

Question

所以，我的问题是，我有一个二维字符数组。我想遍历每个元素，并随机为它们分配一个值。到目前为止，这是我的代码：

private char [][] generateTable(int rows, int columns){

        char [][] table = new char [rows][columns];

        return table;

    }

private void tableFiller(char [][] table){

        for (char[] row : table) {

            for (char character : row) {

                randomize(column);

            }

        }

    }

ublic static void randomize(char character){

        Random random = new Random();

        if (random.nextInt(100) < 50){

            character = '.';

        } else {

            character = '*';

        }

    }

现在，随机生成器方法不起作用，无法弄清楚原因。IDEA 建议我从未使用分配给字符的值，但这无济于事。我怎样才能使这种方法起作用？

Answer 1

这是问题所在：&nbsp;void randomize您的 randomize 方法返回 void，但它应该返回一个字符。然后，应该在调用函数的地方使用该字符，方法是将其分配给相关的数组索引。我建议您基于数组索引进行循环以使分配更容易。例如，而不是：for (char character : row)你会写：for (int i=0; i<row.length; i++)

Answer 2

因为char不是参考。为了让它工作，你应该改变你的 randomize 方法：public static char randomize(){&nbsp; &nbsp; Random random = new Random();&nbsp; &nbsp; char character;&nbsp; &nbsp; if (random.nextInt(100) < 50){&nbsp; &nbsp; &nbsp; &nbsp; character = '.';&nbsp; &nbsp; } else {&nbsp; &nbsp; &nbsp; &nbsp; character = '*';&nbsp; &nbsp; }&nbsp; &nbsp; return character;}并按如下方式调用它：character = randomize();

Answer 3

您需要使用值来设置字符对象 character = randomize(column);private void tableFiller(char [][] table){&nbsp; &nbsp; for (char[] row : table) {&nbsp; &nbsp; &nbsp; &nbsp; for (char character : row) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;character = randomize(column);&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }}或者随机化（字符）；private void tableFiller(char [][] table){&nbsp; &nbsp; for (char[] row : table) {&nbsp; &nbsp; &nbsp; &nbsp; for (char character : row) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;randomize(character);&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }}