像类型一样使用的变量

Question

错误来自 return 语句“'mydata' 是一个变量，但用作类型”如何修复错误？

    [HttpGet]

    public JsonResult NewData()

    {

        List<mydatasample> mydata = new List<mydatasample>(); 

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test2", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });

        return Json(new mydata { }, JsonRequestBehavior.AllowGet);

    }

Answer 1

您正在 return 语句上创建另一个对象。请从返回行中删除 new 关键字和 {}。[HttpGet]public JsonResult NewData(){&nbsp; &nbsp; List<mydatasample> mydata = new List<mydatasample>();&nbsp;&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test2", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; return Json(mydata, JsonRequestBehavior.AllowGet);}

Answer 2

正如评论中所说的错误是在返回&nbsp; &nbsp;[HttpGet]&nbsp; &nbsp; public JsonResult NewData()&nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; List<mydatasample> mydata = new List<mydatasample>();&nbsp;&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test2", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });&nbsp; &nbsp; &nbsp; &nbsp; return Json(mydata, JsonRequestBehavior.AllowGet);&nbsp; &nbsp; }