慕后森
				您可以创建一个function并在 ajaxsuccess函数上调用它,最后有两种方法可以将值放入phpbyform submit或ajax。我使用了 ajax 方法,即: function result(r){//"r" have response value  //pass to ajax alert("i'm in");   $.ajax({      type: "POST",      url: "page1.php",      data: { 'value': r},          success: function(response){      alert("done");    },   error: function (jqXHR) {   console.log(jqXHR);   alert("There was a problem");  }});  }$.ajax({          type: "POST",          url: "page.php",          success: function(response){         //passing response value to function "result"            result(response);        },       error: function (jqXHR) {       console.log(jqXHR);       alert("There was a problem");      } }); 现在page1.php写如下:<?phpsession_start();//putting value in session$_SESSION['url'] = $_POST['value'];   ?>