python for循环随机

Question

lst = ['mylist1','mylist2','mylist3']

for x in lst:

    for r in xrange(2):

        print x

输出：（重复列表中的元素两次）

[root@localhost ~]# python test.py

mylist1

mylist1

mylist2

mylist2

mylist3

mylist3

如何随机元素到：

mylist3

mylist1

mylist3

mylist2

mylist2

mylist1

Answer 1

或*（乘法运算符）：lst = lst*2 # repeat items twiceshuffle(lst)for x in lst:    print(x)或者list comprehension：lst = [x for i in range(2) for x in lst] # repeat items twiceshuffle(lst)for x in lst:    print(x)

Answer 2

您可以首先使用 list 将列表中的每个元素加倍extend()，然后对列表进行洗牌from random import shufflelst = ['mylist1','mylist2','mylist3']lst = lst.extend(lst) # repeat items twiceshuffle(lst)for x in lst:    print(x)