猿问

Flask-paginate 在一页上显示所有结果

我正在尝试为产品页面设置分页,如下所示


from flask_paginate import Pagination, get_page_parameter


...


page = request.args.get(get_page_parameter(), type=int, default=1)


per_page = 4

offset = (page) * 10


search = False

q = request.args.get('q')

if q:

    search = True



pagination = Pagination(page=page, per_page=per_page, offset=offset, total=len(products), 

search=search, record_name='products')


return render_template('products.html', form=form, products=products, 

subcategories=subcategories, pagination=pagination)

而“产品”是从代码中的先前请求中获取的


cur.execute("SELECT * FROM products")

products = cur.fetchall()

但是,在我的产品页面上,我取回了数据库中的所有产品(目前为 20 个),而我可以看到{{ pagination.info }}显示“总共显示 1-4 个产品,共 20 个”。


也{{ pagination.links }}工作正常,因为它显示了功能分页链接,但所有产品仍然在页面上可见。你有什么提示可以解决这个问题吗?


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1回答

尚方宝剑之说

我找到了解决这个问题的方法。也许不是最好的,如果你知道更好的方法,请告诉我。目前,我已经通过以下方式解决了这个问题:# Creating a cursorcur = conn.cursor()# Setting page, limit and offset variablesper_page = 4page = request.args.get(get_page_parameter(), type=int, default=1)offset = (page - 1) * per_page# Executing a query to get the total number of productscur.execute("SELECT * FROM products")total = cur.fetchall()# Executing a query with LIMIT and OFFSET provided by the variables abovecur.execute("SELECT * FROM products ORDER BY added_on DESC LIMIT %s OFFSET %s", (per_page, offset))products = cur.fetchall()# Closing cursorcur.close()...# Setting up the pagination variable, where you are using len(total) to set the total number of # items availablepagination = Pagination(page=page, per_page=per_page, offset=offset, total=len(total), record_name='products')# Render template, where you pass "products" variable# for the prepared query with LIMIT and OFFSET, and passing "pagination" variable as well.return render_template('products.html', form=form, products=products, pagination=pagination)
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