我需要重新构建一些方法来返回客户端列表。我需要那个,因为在那一刻我无法编写任何单元测试。这是我负责将客户端添加到数据库的方法。正如你所看到的,像:name, surname... 这样的值是从已经创建的客户端对象中获取的。 汽车租赁SQL数据库
@Override
public void addClient(Client client) throws SQLException {
preparedStatement = connection.prepareStatement("insert into client" + "(namee, surname, street,houseNumber,city,peselNumber,rentDate, clientNumber)" + "values(?,?,?,?,?,?,?,?)");
preparedStatement.setString(1, client.getName());
preparedStatement.setString(2, client.getSurname());
preparedStatement.setString(3, client.getStreet());
preparedStatement.setInt(4, client.getHouseNumber());
preparedStatement.setString(5, client.getCity());
preparedStatement.setLong(6, client.getPeselNumber());
preparedStatement.setString(7, client.getRentDate());
preparedStatement.setInt(8, client.getClientNumber());
preparedStatement.executeUpdate();
}
这是我负责在屏幕上显示所有客户端的方法: CarRentalSQLDatabase
@Override
public void populateTableViewClients() throws SQLException {
String sql = "SELECT * FROM `client`";
result = statement.executeQuery(sql);
while (result.next()) {
String namee = result.getString("namee");
String surname = result.getString("surname");
String street = result.getString("street");
int houseNumber = result.getInt("houseNumber");
long peselNumber = result.getLong("peselNumber");
String rentDate = result.getString("rentDate");
System.out.println("----------------------------");
System.out.printf("Name:" + namee + "\nSurname:" + surname + "\nStreet:" + street + "\nNumber of house:" + houseNumber + "\nPesel number:" + peselNumber + "\nDate of rental:" + rentDate + "\n");
System.out.println("----------------------------");
}
}
我想构建这样的东西:
public List<Client> getAllCustomers() throws SQLException {
List<Client> listOfClients = new ArrayList<Client>();
String sql = "SELECT * FROM `client`";
result = statement.executeQuery(sql);
//....
return listOfClients;
HUH函数
相关分类