假设我有两个不同的应用程序:
teacher/models.py:
Teacher(models.Model):
name = models.CharField(max_length=300)
class/models.py:
Class(models.Model):
name = models.CharField(max_length=300)
teacher = models.ForeignKey(Teacher)
students = models.ManyToManyField(Student)
我想让所有的老师上课和所有的课程都附上。
我想要的结果:
{[
teacher: '3L' #Teachers Id
classes: ['20L','14L','30L'] #list of Class objects or ids with the above teacher
],
[# similar to above]
}
这是可能的吗?这就是我目前正在做的事情:
classes = Class.objects.all()
teachers = Teacher.objects.filter(id__in=classes.value_list('teacher',flat=True).distinct())
for teacher in teachers:
classes_for_teachers = classes.objects.filter(teacher=teacher)
在上面的代码中,有四个使用循环进行的查询,这无疑增加了时间复杂度。有没有更好的解决方案?提前致谢。
猛跑小猪
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