我正在设置完全有组织的注册表单，我正在尝试将信息发送到我的 MySQL 数据库服务器中。我的代码不起作用，无法弄清楚弹出消息您已注册！
我尝试了几个选项，但没有一个在服务器上工作，
<?php
if (array_key_exists('email', $_POST) or array_key_exists('password', $_POST)) {
// So I'm guessing here need to some additions of based my own inclinatios.
我的代码
<?php
if (array_key_exists('email', $_POST) or array_key_exists('password', $_POST)) {
$link = mysqli_connect("localhost", "id8955440_bigebro", "sunshine1987**", "id8955440_bigebro");
if (mysqli_connect_error()) {
die("There was an error connecting to the database");
}
if ($_POST['email'] == '') {
echo "<p>Email address is required.</p>";
} else if ($_POST['password'] == '') {
echo "<p>Password is required.</p>";
} else {
$query = "SELECT `id` FROM `bigebro` WHERE email = '" . mysqli_real_escape_string($link, $_POST['email']) . "'";
$result = mysqli_query($link, $query);
if (mysqli_num_rows($result) > 0) {
echo "<p>That email address has already been taken.</p>";
} else {
$query = "INSERT INTO `bigebro` (`email`, `password`) VALUES ('" . mysqli_real_escape_string($link, $_POST['email']) . "', '" . mysqli_real_escape_string($link, $_POST['password']) . "')";
if (mysqli_query($link, $query)) {
echo "<p>You have been signed up!";
} else {
echo "<p>There was a problem signing you up - please try again later.</p>";
}
}
}
}
?>
HTML
<form method="post">
<input name="email" type="text" placeholder="Email address">
<input name="password" type="password" placeholder="Password">
<input type="submit" value="Sign up">
</form>
$link = mysqli_connect("localhost", "id8955440_bigebro", "sunshine1987**", "id8955440_bigebro");
当我注册表格时只弹出“注册您时出现问题 - 请稍后再试”我希望从结果中得到“您已注册”。请看报名表
翻翻过去那场雪