我创建了一个应用程序,它涉及与其他人聊天,为了使聊天活动更赏心悦目,我创建了一个ListView更改每条消息的 UI。当我发送一条消息时,第一条消息出现并正确显示,但如果我发送另一条消息,它会覆盖 listView 中的前一条消息,而不是仅向列表视图添加另一个值,这是我的代码:
聊天活动:
private void append_chat_conversation(DataSnapshot dataSnapshot) {
for (DataSnapshot ds : dataSnapshot.getChildren()) {
Log.e("Chat details: ", String.valueOf(ds));
chat_username = dataSnapshot.child("username").getValue(String.class);
chat_msg = dataSnapshot.child("message").getValue(String.class);
Chat chat = new Chat(chat_username, chat_msg);
ArrayList<Chat> chatList = new ArrayList<>();
chatList.add(chat);
chatListAdapter adapter = new chatListAdapter(this, R.layout.chat_message, chatList);
mListView.setAdapter(adapter);
Log.e("Chat username: ", "" + chat_username);
Log.e("Chat message: ", "" + chat_msg);
}
}
聊天列表适配器:
public class chatListAdapter extends ArrayAdapter<Chat> {
private Context mContext;
int mResource;
TextView usernameTV, messageTV;
public chatListAdapter(Context context, int resource, ArrayList<Chat> objects) {
super(context, resource, objects);
mContext = context;
mResource = resource;
}
@NonNull
@Override
public View getView(int position, View convertView, ViewGroup parent) {
String username = getItem(position).getUsername();
String message = getItem(position).getMessage();
Chat chat = new Chat(username, message);
LayoutInflater inflater = LayoutInflater.from(mContext);
convertView = inflater.inflate(mResource, parent, false);
usernameTV = convertView.findViewById(R.id.username_chat);
messageTV = convertView.findViewById(R.id.message_chat);
usernameTV.setText(username);
messageTV.setText(message);
return convertView;
}
}
我不会添加其他代码位(getter 和 setter 或各个消息的实际布局),因为我认为这不是问题。如果您需要其他任何东西,请告诉我,我确定我在这里做了一些愚蠢的事情来实现这一目标,
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