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弹出确认删除php

所以我的代码在下面,它从 dmgeqdelete.php 读取,它将立即从数据库中删除数据。 <td align="center">

<a href="dmgeqdelete.php?damagedID=<?php echo $row["damagedID"]; ?>" >Delete</a>

</td>


我试图为上面的代码添加一个弹出确认。我试过<td align="center">

<a href="dmgeqdelete.php?damagedID=<?php echo $row["damagedID"]; ?>" onclick="return confirm('Are you sure?')">Delete</a>

</td>最终没有任何动作发生


dmgeqdelete.php


<?php

include('dbConfig.php');

$damagedID=$_REQUEST['damagedID'];

$query = "DELETE FROM damagedeq WHERE damagedID=$damagedID"; 

$result = mysqli_query($conn,$query) or die ( mysqli_error());

header("Location: dmgeqview.php"); 

?>

所以我的代码在下面,它从 dmgeqdelete.php 读取,它将立即从数据库中删除数据。 <td align="center">

<a href="dmgeqdelete.php?damagedID=<?php echo $row["damagedID"]; ?>" >Delete</a>

</td>


我试图为上面的代码添加一个弹出确认。我试过<td align="center">

<a href="dmgeqdelete.php?damagedID=<?php echo $row["damagedID"]; ?>" onclick="return confirm('Are you sure?')">Delete</a>

</td>最终没有任何动作发生


dmgeqdelete.php


<?php

include('dbConfig.php');

$damagedID=$_REQUEST['damagedID'];

$query = "DELETE FROM damagedeq WHERE damagedID=$damagedID"; 

$result = mysqli_query($conn,$query) or die ( mysqli_error());

header("Location: dmgeqview.php"); 

?>

展开片段

完整代码


<?php

include('dbConfig.php');

?>

<!DOCTYPE html>

<html>


<head>

  <meta charset="utf-8">

  <title>View Damaged Equipment Records</title>

  <link rel="stylesheet" href="css/style.css" />

</head>


<body>

  <div class="form">

    <p><a href="report.php">Home</a> | <a href="index.php">Logout</a></p>

    <h2>View Records</h2>

    <table width="100%" border="1" style="border-collapse:collapse;">

      <thead>

        <tr>

          <th><strong>No</strong></th>

          <th><strong>Damage ID's</strong></th>

          <th><strong>EQ ID's</strong></th>

          <th><strong>Student ID's</strong></th>

          <th><strong>Staff ID's</strong></th>

          <th><strong>Date reported</strong></th>

    /tr>

          <?php $count++; } ?>

      </tbody>

    </table>

  </div>

</body>


</html>


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