我正在开发一个基于 python 的 discord bot,它具有以下命令
@client.command(name="Mine",
description="Mine daily.",
brief="Mine daily.",
aliases=['mine', 'm'],
pass_context=True)
@commands.cooldown(1, 30, commands.BucketType.user)
async def mine(ctx, arg):
<content>
但是当用户达到命令的 30 秒速率限制时,它会将错误输出到 python shell
Ignoring exception in command Mine
Traceback (most recent call last):
File "C:\Users\raner\AppData\Local\Programs\Python\Python36\lib\site-
packages\discord\ext\commands\bot.py", line 846, in process_commands
yield from command.invoke(ctx)
File "C:\Users\raner\AppData\Local\Programs\Python\Python36\lib\site-
packages\discord\ext\commands\core.py", line 367, in invoke
yield from self.prepare(ctx)
File "C:\Users\raner\AppData\Local\Programs\Python\Python36\lib\site-
packages\discord\ext\commands\core.py", line 351, in prepare
raise CommandOnCooldown(bucket, retry_after)
discord.ext.commands.errors.CommandOnCooldown: You are on cooldown. Try
again in 28.58s
我想要做的是获得剩余的冷却时间并将其放入可以在不和谐时回复给用户的内容,例如“此命令受速率限制,请在 28.58 秒后重试”
我在网上找不到太多帮助,而且大部分已经过时或似乎不起作用。
ITMISS
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