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如何阻止我的拖尾线导致对象因数组大小而变慢

随着数组变大,我在画布上的方形对象会急剧变慢。该数组用于存储先前的 x,y 位置,然后拖尾线使用这些位置来绘制自身。


有没有办法让我的对象以相同的速度移动,同时保持整个拖尾线,即我不希望拖尾线在任何时间点消失/消失。


<!DOCTYPE html>

<html>

<head>

<meta name="viewport" content="width=device-width, initial-scale=1.0"/>

<style>

canvas {

    border:1px solid #d3d3d3;

    background-color: #f1f1f1;

}

</style>

</head>

<body onload="startGame()">

<script>


var myGamePiece;

var myArrayX = [];

var myArrayY = [];


function startGame() {

    myGamePiece = new component(30, 30, "red", 10, 120);

    myGameArea.start();

}


var myGameArea = {

    canvas : document.createElement("canvas"),

    start : function() {

        this.canvas.width = 480;

        this.canvas.height = 270;

        this.context = this.canvas.getContext("2d");

        document.body.insertBefore(this.canvas, document.body.childNodes[0]);

        this.interval = setInterval(updateGameArea, 20);

    },

    clear : function() {

        this.context.clearRect(0, 0, this.canvas.width, this.canvas.height);

    }

    }





function component(width, height, color, x, y) {

    this.width = width;

    this.height = height;

    this.speedX = 0;

    this.speedY = 0;

    this.x = x;

    this.y = y;    

    this.update = function() {

        ctx = myGameArea.context;

        ctx.fillStyle = color;

        ctx.fillRect(this.x, this.y, this.width, this.height);


         // testing:

    ctx.beginPath();

    ctx.strokeStyle = "red";

    ctx.setLineDash([5,5]);

    ctx.moveTo(10, 120);

    var arrLength = myArrayX.length;

    for(var i=0; i<arrLength;i+=1){

    ctx.lineTo(myArrayX[i], myArrayY[i]);

    ctx.stroke();

    }


    }

    this.newPos = function() {

        this.x += this.speedX;

        this.y += this.speedY;  

        myArrayX.push(this.x);

        myArrayY.push(this.y);

    }   

    //end test

}


function updateGameArea() {

    myGameArea.clear();

    myGamePiece.newPos();    

    myGamePiece.update();

    document.getElementById("test").innerHTML = "size of array: " + (myArrayX.length -1).toString()


}


隔江千里
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