我目前正在用java在初学者编程课上做一个项目。该项目涉及制造自动售货机。本质上,自动售货机会询问您想要什么商品,然后它会向您要钱。每当有人选择某件商品时,该商品的数量就会减少一个。我想要做的是让它在某个商品缺货(数量为0)时,代码返回到开头并再次询问您想要什么商品。我也想这样做,如果有人输入无效数字,代码也会重新启动。我该怎么做?这是代码。
import java.util.Scanner;
public class VendingMachine {
public static void main(String[] args) {
Scanner user_input = new Scanner(System.in);
int potatoChips = 0;
int cookies = 3;
int candies = 4;
int quarters;
int dimes;
int nickels;
System.out.println("Select the number for the item you would like");
System.out.println("For Potato Chips, Enter 1");
System.out.println("For Cookies, Enter 2");
System.out.println("For Candies, Enter 3");
int itemSelection = user_input.nextInt();
if (itemSelection == 1) {
if (potatoChips > 0) {
potatoChips = potatoChips - 1;
System.out.println("You chose potato chips.");
System.out.println("That will be $1.25");
System.out.println("How many quarters do you have?");
quarters = user_input.nextInt();
System.out.println("How many dimes do you have?");
dimes = user_input.nextInt();
System.out.println("How many nickels do you have?");
nickels = user_input.nextInt();
int nickelsToPennies = (nickels * 5);
int dimesToPennies = (dimes * 10);
int quartersToPennies = (quarters * 25);
int pennies = (nickelsToPennies + dimesToPennies + quartersToPennies);
if (pennies < 125) {
System.out.println("You have not entered enough money. Have a great day.");
}
else if (pennies == 125 ) {
System.out.println("Here is your snack. Have a great day");
}
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