手动生成的JSON有效，但是通过json.dumps创建的JSON即使输出看起来完全相同也不起作用

Question

我正在Marketo通过 Python 库marketo-rest-python使用API 。我可以创建潜在客户并通过以下基本代码更新它们：

leads = [{"email":"[e-mail]","firstName":"Joe"},{"email":"[e-mail]","firstName":"Jill"}]

lead = mc.execute(method='create_update_leads', leads=leads, action='createOnly', lookupField='email', 

                asyncProcessing='false', partitionName='Default')

当我以编程方式创建这个“引导”JSON 对象时

leads = []

lead = {}

lead['email'] = "[e-mail]"

lead['firstName'] = "Joe"

leads.append(lead)

lead = {}

lead['email'] = "[e-mail]"

lead['firstName'] = "Jill"

leads.append(lead)

json_leads = json.dumps(leads, separators=(',', ':'))

print(json_leads)

然后，Microsoft Azure Databricks中的输出完全相同，但是Marketo系统向我返回609->无效JSON。

我的输出看起来像

[{"email":"[e-mail]","firstName":"Joe"},{"email":"[e-mail]","firstName":"Jill"}]

它与示例中的完全相同。当我使用示例JSON代码行时，它可以工作，但是我自己生成的JSOn不起作用。

任何人都知道这会是什么？我在 Microsoft Azure Databricks 中使用 Python。

Answer 1

我相信你不需要打电话json.dumps，就这样做leads = []lead = {}lead['email'] = "[e-mail]"lead['firstName'] = "Joe"leads.append(lead)lead = {}lead['email'] = "[e-mail]"lead['firstName'] = "Jill"leads.append(lead)lead = mc.execute(method='create_update_leads', leads=leads, action='createOnly', lookupField='email', asyncProcessing='false', partitionName='Default')