从Laravel 5.8表单的复选框传递布尔值

Question

我尝试在创建新的帖子时保存布尔值，然后在更新帖子时让它更新值。当我创建一个新的帖子并保存时，它会持久保存到数据库中，甚至可以更新它而不会出现问题。我在处理复选框布尔值时遇到了一些麻烦。这是我在拉拉韦尔（Laravel）的拳头项目，这是我确定的障碍之一。

图式

...

public function up()

    {

        Schema::create('posts', function (Blueprint $table) {

            $table->increments('id');

            $table->unsignedBigInteger('user_id');

            $table->string('title');

            $table->text('body')->nullable();

            $table->string('photo')->nullable();

            $table->boolean('is_featured')->nullable()->default(false);

            $table->boolean('is_place')->nullable()->default(false);

            $table->string('tag')->nullable()->default(false);

            $table->timestamps();

        });

        Schema::table('posts', function (Blueprint $table) {

            $table->foreign('user_id')->references('id')->on('users');

        });

    }

...

PostController.php

...

public function store(Request $request)

    {

        $rules = [

            'title' => ['required', 'min:3'],

            'body' => ['required', 'min:5']

        ];

        $request->validate($rules);

        $user_id = Auth::id();

        $post = new Post();

        $post->user_id = $user_id;

        $post->is_featured = request('is_featured');

        $post->title = request('title');

        $post->body = request('body');

        $post->save();

        $posts = Post::all();

        return view('backend.auth.post.index', compact('posts'));

    }

...

post / create.blade.php

...

<input type="checkbox" name="is_featured" class="switch-input"

       value="{{old('is_featured')}}">

...

Answer 1

您不清楚问题到底是什么，但是您可以在模型中将属性强制转换为布尔值。<?phpnamespace App;use Illuminate\Database\Eloquent\Model;class Post extends Model{&nbsp; &nbsp; protected $casts = [&nbsp; &nbsp; &nbsp; &nbsp; 'is_featured' => 'boolean',&nbsp; &nbsp; &nbsp; &nbsp; 'is_place' => 'boolean',&nbsp; &nbsp; ];}然后，在表单中，您将需要检查该值以确定是否已选中该框。<input type="checkbox" name="is_featured" class="switch-input" value="1" {{ old('is_featured') ? 'checked="checked"' : '' }}/>在您的控制器中，您只想检查输入是否已提交。未经检查的输入将不会被加总。$post->is_featured = $request->has('is_featured');

Answer 2

试试这个&nbsp;$post->is_featured = $request->input('is_featured') ? true : false;