使用php登录成功后如何重定向到新页面

Question

我会简短明了，因为无论发布什么内容，我似乎都被禁止了。我在这里发现了类似的问题，但是所有建议都与我的代码无关。

登录成功重定向到新页面后，我只需要帮助即可。

 $username = $_POST["username"]; 

    $conn = mysqli_connect($host, $user, $pass, $db);

    $query = "SELECT * FROM user WHERE username = '" .$username.  "'";

    $result = mysqli_query($conn,$query);

    while ($row = mysqli_fetch_assoc($result)){

        echo "Password Entered: " . $_POST["password"];

        echo "Correct Pasword: " . $row['password'];

        // See if the password is correct

        if ($_POST["password"] === $row['password'])

            echo "Logon Successful!";

        else {

            echo "Logon Failed!";

        }

    }

     if (!mysqli_fetch_assoc($result))

        echo "Invalid Username";

?>

Answer 1

我只是忘了标题后面的分号。$query = "SELECT * FROM user WHERE username = '" .$username.  "'";$result = mysqli_query($conn,$query);while ($row = mysqli_fetch_assoc($result)){    // See if the password is correct    if  ($_POST["password"] === $row['password']){        echo "Logon Successful!";        header("Location: index.php");         exit();    }

Answer 2

可能会有一些变化，如下所示：login.php$username = $_POST["username"]; $password = $_POST["password"];$conn = mysqli_connect($host, $user, $pass, $db);$query = "SELECT * FROM user WHERE username = '" . $username .  "'";$result = mysqli_query($conn,$query);while ($row = mysqli_fetch_assoc($result)){    // See if the password is correct    if ($password === $row['password']){        header('location: login_successful.php');    }else {        // you can hide the message at QueryString via SESSION or COOKIE        header('location: login_form.php?message=FAIL_MESSAGE');  //you can detect and show login status message.    }}