按对象属性过滤对象数组

Question

我有很多物体

const countryList =  [

    { name: 'Afghanistan', id: 'AF' },

    { name: 'Åland Islands', id: 'AX' },

    { name: 'Albania', id: 'AL' },

    { name: 'Algeria', id: 'DZ' }]

我想按对象“ id”过滤数组并获取名称

这是我已经完成的工作

getName = (id) => {

    let name=[]

    for (var i = 0; i < countryList.length ; i++) {

        if (countryList[i].id === id) {

            name.push(countryList[i]);                

        } 

    }

    console.log(name[0].name)

}

有什么更好的方法吗？

Answer 1

您可以找到名称（如果名称id是唯一的），并将未知对象作为默认对象。const&nbsp; &nbsp; getName = id => (countryList.find(o => o.id === id) || {}).name,&nbsp; &nbsp; countryList = [{ name: 'Afghanistan', id: 'AF' }, { name: 'Åland Islands', id: 'AX' }, { name: 'Albania', id: 'AL' }, { name: 'Algeria', id: 'DZ' }];console.log(getName('AL'));console.log(getName('UK'));

Answer 2

如果国家/地区ID是唯一的，则出于性能原因，您可以使用array.some。getCountryName = (countryList, id) => {&nbsp; &nbsp; name = null;&nbsp; &nbsp; countryList.some((x, idx) => {&nbsp; &nbsp; &nbsp; &nbsp; result = false;&nbsp; &nbsp; &nbsp; &nbsp; if(x.id === id) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; name = x.name;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; result = true;&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; return result;&nbsp; &nbsp; });&nbsp; &nbsp; return name;}用法是getCountryName(countryList, 'AF')结果是'Afghanistan'