没有数组的序列中的最大最小ODD数

Question

我正在尝试从输入序列中获取最大和最小ODD数，而不使用数组，请告知我应该添加什么，我正在使用以下代码：

System.out.print("Enter odd integers(even to Stop): " );

do {

    num = input.nextInt();

    sum += num;

} while (num % 2 != 0);

if (num < min) {

    min = num;                

}

if (num > max) {

    max = num;

}

System.out.print("Minimum Odd Number: " + min + ";");

System.out.println("Maximum Odd Number: " + max);

System.out.print("Sum: " + sum);

Answer 1

您检查逻辑值，以可能将其记录为最小值或最大值的逻辑应该在循环内：int min = Integer.MAX_VALUE;int max = Integer.MIN_VALUE;int num = input.nextInt();while (num % 2 != 0) {&nbsp; &nbsp; sum += num;&nbsp; &nbsp; if (num < min) {&nbsp; &nbsp; &nbsp; &nbsp; min = num;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;&nbsp; &nbsp; }&nbsp; &nbsp; if (num > max) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp;max = num;&nbsp; &nbsp; }&nbsp; &nbsp; num = input.nextInt();}System.out.print("Minimum Odd Number: " + min + ";");System.out.println("Maximum Odd Number: " + max);System.out.print("Sum: " + sum);作为注释，我将min和max分别初始化为最大和最小整数值。这样可以确保我们正确捕获最开始的输入，无论它们是什么。