解析Java中的XML字符串

Question

我正在尝试解析以下字符串以获得“ orderNo”

String requestBody="<?xml version="1.0" encoding="UTF-8" standalone="yes"?><ShipmentList><Shipment ActualShipmentDate="2018-06-26T11:25:00+05:30" DocumentType="0005" TotalWeight="55.5" TotalWeightUOM="LB" TrackingNo="9461236897846412938163"><ShipmentLines><ShipmentLine OrderNo="1529904772887" PrimeLineNo="1" Quantity="3" SubLineNo="1"/><ShipmentLine OrderNo="1529904772887" PrimeLineNo="2" Quantity="3" SubLineNo="1"/><ShipmentLine OrderNo="1529904772887" PrimeLineNo="3" Quantity="3" SubLineNo="1"/><ShipmentLine OrderNo="1529904772887" PrimeLineNo="4" Quantity="3" SubLineNo="1"/><ShipmentLine OrderNo="1529904772887" PrimeLineNo="5" Quantity="3" SubLineNo="1"/></ShipmentLines><Extn ExtnPackageASN="55538770655551006451" ExtnPackageID="6247442951596360944" ExtnPackLength="25.0" ExtnLengthUOM="IN" ExtnPackWidth="20.0" ExtnWidthUOM="IN" ExtnPackHeight="16.0" ExtnHeightUOM="IN" ExtnCarrierMethodId="83"/></Shipment></ShipmentList>";

NodeList nl = null;

        try {

            DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();

            DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

            DocumentBuilder builder = factory.newDocumentBuilder();

            Document doc = builder.parse(requestBody);

            XPathFactory xPathfactory = XPathFactory.newInstance();

            XPath xpath = xPathfactory.newXPath();

            XPathExpression expr = xpath.compile("//ShipmentList/Shipment/ShipmentLines/ShipmentLine[@OrderNo]");

            nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);

        } catch (XPathExpressionException e1) {

            // TODO Auto-generated catch block

            e1.printStackTrace();

        } catch (ParserConfigurationException e1) {

            // TODO Auto-generated catch block

            e1.printStackTrace();

        } catch (SAXException e1) {

我已经尝试使用上面的代码片段，但是有人可以让我知道这是什么错误，这并没有帮助

Answer 1

首先："必须像\"Java String中那样转义字符。requestBody字符串必须看起来像：&nbsp;String requestBody="<?xml version=\"1.0\" encoding=\"UTF-8\" ...，依此类推。然后是主要错误：Document doc = builder.parse(requestBody);builder解析的不是String而是该String表示的URL。因此，请改用以下InputStream示例：Document&nbsp;doc&nbsp;=&nbsp;builder.parse(new&nbsp;ByteArrayInputStream(requestBody.getBytes()));然后您将获得五个<ShipmentLine>节点。