我应该在这里使用哪种算法？在字符串数组中查找字符串

Question

我有2个数组。

一个Array有字符串，我在找。

static String[] namesToLookFor = { "NR", "STAFFELNR", "VONDATUM"};

另一个Array有字符串，我是从* .csv文件中获得的。

indexString = indexReader.readLine();

indexArray = indexString.split(";");

我的目标是实现system.out.println() ，indexArray[]而不是的价值观namesToLookFor[]。

例如：

namesToLookFor = {"NR"};

indexArray = {"HELLO","NR"};

//Any Algorithm here...

因此，在这种情况下"HELLO"应将其打印出来，因为它不在namesToLookFor[]数组中。

Answer 1

您可以遍历indexArray并检查每个元素是否包含在namesToLookFor数组中：&nbsp; &nbsp; String[] namesToLookFor = {"NR"};&nbsp; &nbsp; String[] indexArray = {"HELLO","NR"};&nbsp; &nbsp; List<String> excludedNames = Arrays.asList(namesToLookFor);&nbsp; &nbsp; for(String s : indexArray) {&nbsp; &nbsp; &nbsp; &nbsp; if (!excludedNames.contains(s)) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; System.out.println(s);&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }将仅输出“ HELLO”。

Answer 2

如果您使用的是Java8，则可以执行以下操作List<String> list = Arrays.asList(namesToLookFor);Arrays.stream(indexArray)&nbsp; &nbsp; &nbsp; &nbsp; .filter(item -> !list.contains(item))&nbsp; &nbsp; &nbsp; &nbsp; .forEach(System.out::println);

Answer 3

// Put array into set for better performanceSet<String> namesToFilter = new HashSet<>(Arrays.asList("NR", "STAFFELNR"));String[] indexArray = indexReader.readLine().split(";");// Create list with unfiltered values and remove unwanted onesList<String> resultList = new ArrayList<>(indexArray);resultList.removeAll(namesToFilter);// Do with result whatever you wantfor (String s : resultList)&nbsp; &nbsp; System.out.println(s);