如何按顺序添加元素数组？

Question

我有一个数组：const arr = [1, 2, 5, 10];

我如何将其转换为const arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]？

Answer 1

const arr = [1, 2, 5, 10];for(let i = 1; i <= 10; i++) { // Loop from 1 till 10, including 10&nbsp; &nbsp; if (!arr.includes(i)) { // If arr does not include 'i'&nbsp; &nbsp; &nbsp; &nbsp; arr.splice(i - 1, 0, i); // We insert it into the array&nbsp; &nbsp; &nbsp; &nbsp; // -1, because arrays start at 0&nbsp; &nbsp; }}

Answer 2

一种无需对迭代次数进行硬编码的简单方法是从数组中获取最小值和最大值，然后在它们之间填充数字。这是做到这一点的一种方法const arr = [1, 2, 5, 10];var highest = Math.max(...arr);var minimum = Math.min(...arr);var output = [];for(var i = minimum; i <= highest; i++){&nbsp; output.push(i);}console.log(output);

Answer 3

您可以采用嵌套while语句并拼接缺失的项目。var array = [1, 2, 5, 10],&nbsp; &nbsp; i = array.length;while (i--) while (array[i - 1] + 1 < array[i]) array.splice(i, 0, array[i] - 1);console.log(...array);