我完美地创建了动态微调器,如下所示
k++;
flag=k;
final LinearLayout.LayoutParams lparams = new
LinearLayout.LayoutParams(380,120);
lparams.setMargins(1, 20, 1, 0);
colorSpinner[flag] = new Spinner(getActivity());
colorSpinner[flag].setLayoutParams(lparams);
colorSpinner[flag].setId(flag);
colorSpinner[flag].setAdapter(new ArrayAdapter<String>(getContext(), android.R.layout.simple_spinner_dropdown_item, color_list));
loadColorSpinnerData(URL);
colorSpinner[flag].setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
@Override
public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l)
{
color_id = datalist1.get(i).getId();
}
@Override
public void onNothingSelected(AdapterView<?> adapterView) {
// DO Nothing here
}
});
mLayout.addView(colorSpinner[flag]);
color_array.add(colorSpinner[flag]);
如何获取数组中的颜色ID
这是行不通的
String[] Acolorid = new String[color_array.size()];
for(int i = 0; i < color_array.size(); i++){
Acolorid[i] = String.valueOf(color_array.get(i).getSelectedItemPosition()+1); //Acolorid[j]= String.valueOf(color_id);//color_array.get(i).getSelectedItem().toString();
Hcolorid=String.join(",",Acolorid);
}
请给我我想获取数组中的颜色ID而不获取项目位置的解决方案。
喵喔喔
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