我想根据员工姓名打印负责人的姓名

Question

我想动态地打印Sumita Nath的Abhishek的头像，但是不显示头像。为什么会这样呢？我用不同的方法尝试了很多次，但是没有显示输出。这是我的数据：

   $employee = array

(

0=>

    array("employee_id"=>1, "firstName"=>"Zahir", "lastName"=>"Alam", "Age"=>25, "Company"=>"Switchme", "Role"=>"Developer", "Department"=>"Tech"

        ,"Head"=>

            array("Id"=>3 , "Name"=>"Sourasis Roy")

    )

,

1=>

    array("employee_id"=>2, "firstName"=>"Amith", "lastName"=>"Manniken", "Age"=>25, "Company"=>"Switchme", "Role"=>"Developer", "Department"=>"Tech"

        ,"Head"=>

            array("Id"=>3 , "Name"=>"Sourasis Roy")

    )

,

2=>

    array("employee_id"=>3, "firstName"=>"Sourasis", "lastName"=>"Roy", "Age"=>28, "Company"=>"Switchme", "Role"=>"CTO")

,

3=>

    array("employee_id"=>4, "firstName"=>"Aditya", "lastName"=>"Mishra", "Age"=>29, "Company"=>"Switchme", "Department"=>"Tech", "Role"=>"CEO")

,

4=>

    array("employee_id"=>5, "firstName"=>"Priti", "lastName"=>"Lata", "Age"=>24, "Company"=>"Switchme", "Role"=>"HR")

,

5=>

    array("employee_id"=>6, "firstName"=>"Sumita", "lastName"=>"Nath", "Age"=>24, "Company"=>"Switchme", "Role"=>"HLA Head", "Department"=>"Crm")

,

6=>

    array("employee_id"=>7, "firstName"=>"Tarini", "lastName"=>"Khanna", "Age"=>22, "Company"=>"Switchme", "Role"=>"Content Writer")

,

7=>

    array("employee_id"=>8, "firstName"=>"Abhisek", "lastName"=>"Soni", "Age"=>23, "Company"=>"Switchme", "Role"=>"HLA", "Department"=>"Crm","Head"=>array("Id"=>5 , "Name"=>"Sumita Nath")

    )

    );

这就是我尝试过的：

$name="Abhishek";

echo "The Head of ";

echo $name;

echo " is ";

$key = array_search($name, array_column($employee, 'Head','Name'));

//print $employee[7]["Head"echo array_]["Name"];

echo $key;