试图将这个要点转换为红宝石，这是我的代码：
$char_map = ('!.' + '0123456789' + 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' + 'abcdefghijklmnopqrstuvwxyz').scan(/./)
$int_map = Hash.new
$char_map.each_with_index {|v,k| $int_map[v] = k }
$cutoff = ($char_map.count) - 11
# Converts an integer to its text-encoded form.
def to_chars(value)
if value < $cutoff
return $char_map[value]
end
value -= $cutoff
out = []
while value != 0
value, rem = value.divmod($char_map.count)
out.push($char_map[rem])
end
# handle when value == cutoff
if !out
out.push($char_map[value])
end
out.push($char_map[$cutoff + out.count - 1])
out.reverse!
return out.join('')
end
# Converts characters from the provided string back into their integer
# representation, and returns both the desired integer as well as the number
# of bytes consumed from the character string (this function can accept a
# string that is the result of a concatenation of results from to_chars() ).
def to_val(chars)
chars = chars.scan(/./)
first = $int_map[chars[0]]
if first < $cutoff
return first, 1
end
first -= $cutoff - 1
dec = []
for ch in chars[1..1+first] do
dec.push($int_map[ch])
end
value = dec.pop() + $cutoff
m = $char_map.count
while dec != []
value += m * dec.pop()
m *= $char_map.count
end
return value, first + 1
end
# Converts a sequence of integers into a string that represents those
# integers.
def from_sequence(lst)
lst.map! {|int| to_chars(int)}
return lst.join('')
end
# Converts a string that rappresents a sequence of integers back into a
# a list of integers
def from_string(str)
out = []
i = 0
while i < str.length
this, used = to_val(str[i, str.length - i])
out.push(this)
i += used
end
return out
end
p to_chars(123456789)
p to_val(to_chars(123456789))
p from_string(from_sequence([123456789,4688]))
（对全局变量很抱歉...仅适用于测试，前提是所有工作都适合自己的班级）
错误在最后一行，而不是打印回[123456789, 4688]数组打印[7901231212, 4688]
为什么？错误在哪里？
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