如何找到用<tag>…</>指定的字符的字符位置？Python

Question

我想获得的位置<，并>认为是真实的tag，当它们被嵌入在这样的事情<tag "510270">calculate</>。

我有这样的句子：

sentence = "After six weeks and seventeen tentative approaches the only serious 

tender came from Daniel. He had offered a paltry #2 a week for the one-time 

woodman's home, sane enough in this, at least, to <tag "510270">calculate</> 

safety to the nearest new penny piece. "

sentence2 = "After six weeks and seventeen tentative approaches the only serious 

tender came from Daniel. He had offered a paltry #2 a week for the one-time 

woodman's < home, sane enough in this, at least, to <tag "510270">calculate</> 

safety to the nearest new penny > piece. "

sentence3 = "After six weeks and seventeen tentative approaches the only serious 

tender came from Daniel. He had offered a paltry #2 a week for the one-time 

woodman's > home, sane enough in this, at least, to <tag "510270">calculate</> 

safety to the nearest new penny < piece. "

我需要的cfrom和incfrom是和第一的位置第2<内的<tag "XXXX">...</>，我需要的CTO和incto是第1第2的位置和>内<tag "XXXX">...</>

对于句子2和句子3之类的句子，该句子在哪里出现<或>出现在哪里，我该<tag "XXXX">...</>怎么办？

对于句子1，我可以简单地做到这一点：

cfrom,cto = 0,0

for i,c in enumerate(sentence1):

  if c == "<":

    cfrom == i

  break

for i,c in enumerate(sentence1.reverse):

  if c == ">":

    cto == len(sentence)-i

  break

incfrom incto = 0,0

fromtrigger, totrigger = False, False

for i,c in enumerate(sentence1[cfrom:]):

  if c == ">":

    incfrom = cfrom+i

  break

for i,c in enumerate(sentence1[incfrom:cto]):

  if c == "<":

    incto = i

  break

Answer 1

如果我正确理解这一点，则应该可以正常工作（假设您不更改变量i ,c）cfrom,cto = 0,0for i,c in enumerate(sentence1):&nbsp; if c == "<tag":&nbsp; &nbsp; cfrom == i&nbsp;&nbsp; breakfor i,c in enumerate(sentence1):&nbsp; if c == ">":&nbsp; &nbsp; cto == i \\going forward from cfrom&nbsp; breakincfrom incto = 0,0fromtrigger, totrigger = False, Falsefor i,c in enumerate(sentence1[cto:]):\\after the tag is opened, look for the start of closing tag&nbsp; if c == "</":&nbsp; &nbsp; incfrom = i&nbsp; breakfor i,c in enumerate(sentence1[cto:]):&nbsp; if c == ">":&nbsp; &nbsp; incto = i&nbsp; break