Django重定向登录后无法正常工作“下一步”不发布？

Question

我有一个登录页面，除了重定向到引荐来源页面外，其他都运行正常。用户在应用程序内收到带有直接链接的电子邮件，他们（在此示例中）尚未登录，并被重定向到登录页面。成功登录后，用户将被重定向到硬编码路径。请参见下面的示例。

电子邮件中的网址： http://localhost:8000/issueapp/1628/view/22

登录页面的URL： http://localhost:8000/login?next=/issueapp/1628/view/22

登录视图（带有硬编码的重定向）：

def login_user(request):    

    state = "Please log in below..."

    username = password = ''

    if request.POST:

        username = request.POST['username']

        password = request.POST['password']

        user = authenticate(username=username, password=password)

        if user is not None:

            if user.is_active:

                login(request, user)

                state = "You're successfully logged in!"

                return HttpResponseRedirect('/issueapp/1628/')

            else:

                state = "Your account is not active, please contact the site admin."

        else:

            state = "Your username and/or password were incorrect."

    return render_to_response(

        'account_login.html',

        {

        'state':state,

        'username': username

        },

        context_instance=RequestContext(request)

    )

登录视图（带有“下一步”重定向）：

def login_user(request):    

    state = "Please log in below..."

    username = password = ''

    if request.POST:

        username = request.POST['username']

        password = request.POST['password']

        user = authenticate(username=username, password=password)

        if user is not None:

            if user.is_active:

                login(request, user)

                state = "You're successfully logged in!"

                return HttpResponseRedirect(request.GET['next'])

            else:

                state = "Your account is not active, please contact the site admin."

        else:

            state = "Your username and/or password were incorrect."

上面的视图导致一个异常"Key 'next' not found in <QueryDict: {}>"。即使在url和表单中，该表单似乎也没有发布“ next”变量。我已经搜索并四处张望，无法弄清为什么它不起作用。有任何想法吗？

Answer 1

您的代码很好，唯一的问题是，next因为方法是，所以您以表单的形式将属性传递为帖子post。在视图中，您尝试next在get字典中获取显然不存在的参数。您必须action像这样声明html表单，以便您的视图工作。{% if next %}<form action="/login/?next={{next}}" method="post" >{%else%}<form action="/login/" method="post" >{% endif %}&nbsp; &nbsp; &nbsp; &nbsp; {% csrf_token %}&nbsp; &nbsp; &nbsp; &nbsp; username:&nbsp; &nbsp; &nbsp; &nbsp; <input type="text" name="username" value="{{ username }}" /><br />&nbsp; &nbsp; &nbsp; &nbsp; password:&nbsp; &nbsp; &nbsp; &nbsp; <input type="password" name="password" value="" /><br />&nbsp; &nbsp; &nbsp; &nbsp; <input type="submit" value="Log In"/>&nbsp; &nbsp; &nbsp; &nbsp; {% debug %}&nbsp; &nbsp; </form>在那里，如果有一个next变量，则将其包含在其中url以作为获取参数来进行检索。如果没有，则表单不包含它。这是最好的方法，但是您也可以通过next从POST字典中请求这样来在视图中解决此问题：return HttpResponseRedirect(request.POST.get('next'))请注意，这仅在模板account_login 具有名为的变量时才有效next。您应该在视图中生成它，并在渲染它时将其传递给模板。通常，在模板中，您将执行以下操作：# this would be hardcodednext = '/issueapp/1628/view/22'# you may add some logic to generate it as you need.然后您执行以下操作：return render_to_response(&nbsp; &nbsp; 'account_login.html',&nbsp; &nbsp; {&nbsp; &nbsp; 'state':state,&nbsp; &nbsp; 'username': username,&nbsp; &nbsp; 'next':next&nbsp; &nbsp; },&nbsp; &nbsp; context_instance=RequestContext(request))希望这可以帮助！

Answer 2

如果您想变得更通用，则可以执行以下操作，在发布表单时，它会传递任何GET参数：<form action="/path-to-whatever/{% if request.GET %}?{{ request.GET.urlencode }}{% endif %}" method="post">