就像标题所暗示的那样，我正在尝试动态生成Facebook Open Graph元标记，但无法使其正常工作。可能吗？
更新：
最终，我在@saccharine的帮助下使其工作。以下代码为我工作：
<?php
$params = array();
if(count($_GET) > 0) {
$params = $_GET;
} else {
$params = $_POST;
}
// defaults
if($params['type'] == "") $params['type'] = "restaurant";
if($params['locale'] == "") $params['locale'] = "en_US";
if($params['title'] == "") $params['title'] = "default title";
if($params['image'] == "") $params['image'] = "thumb";
if($params['description'] == "") $params['description'] = "default description";
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head prefix="og: http://ogp.me/ns# fb: http://ogp.me/ns/fb# MY_APP_NAME_SPACE: http://ogp.me/ns/fb/MY_APP_NAME_SPACE#">
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/>
<!-- Open Graph meta tags -->
<meta property="fb:app_id" content="MY_APP_ID" />
<meta property="og:site_name" content="meta site name"/>
<meta property="og:url" content="http://mysite.com/index.php?type=<?php echo $params['type']; ?>&locale=<?php echo $params['locale']; ?>&title=<?php echo $params['title']; ?>&image=<?php echo $params['image']; ?>&description=<?php echo $params['description']; ?>"/>
<meta property="og:type" content="MY_APP_NAME_SPACE:<?php echo $params['type']; ?>"/>
<meta property="og:locale" content="<?php echo $params['locale']; ?>"/>
<meta property="og:title" content="<?php echo $params['title']; ?>"/>
<meta property="og:image" content="http://mysite.com/img/<?php echo $params['image']; ?>.png"/>
<meta property="og:description" content="<?php echo $params['description']; ?>"/>
</head>
</html>
我现在放入Facebook调试器中的url可以包含任何动态参数，甚至可以不包含任何动态参数，甚至可以包括所有选择，也可以仅包含选择，并且可以按如下顺序进行：
http : //mysite.com/index.php?type=restaurant&title= luigis