我正在使用OpenCV来获取捕获帧的鸟瞰图。这是通过在飞机上提供棋盘图案来完成的，该棋盘图案将形成鸟瞰图。
尽管看起来相机已经很漂亮了，但是我需要它完美以确定像素和厘米之间的关系。
在下一阶段，捕获帧将被扭曲。它给出了预期的结果：
但是，通过执行此转换，棋盘图案外部的数据将丢失。我需要的是旋转图像，而不是扭曲已知的四边形。
问题：如何以摄像机角度旋转图像以使其自上而下？
一些代码来说明我目前正在做什么：
Size chessboardSize = new Size(12, 8); // Size of the chessboard
Size captureSize = new Size(1920, 1080); // Size of the captured frames
Size viewSize = new Size((chessboardSize.width / chessboardSize.height) * captureSize.height, captureSize.height); // Size of the view
MatOfPoint2f imageCorners; // Contains the imageCorners obtained in a earlier stage
Mat H; // Homography
找到角落的代码：
Mat grayImage = new Mat();
//Imgproc.resize(source, temp, new Size(source.width(), source.height()));
Imgproc.cvtColor(source, grayImage, Imgproc.COLOR_BGR2GRAY);
Imgproc.threshold(grayImage, grayImage, 0.0, 255.0, Imgproc.THRESH_OTSU);
imageCorners = new MatOfPoint2f();
Imgproc.GaussianBlur(grayImage, grayImage, new Size(5, 5), 5);
boolean found = Calib3d.findChessboardCorners(grayImage, chessboardSize, imageCorners, Calib3d.CALIB_CB_NORMALIZE_IMAGE + Calib3d.CALIB_CB_ADAPTIVE_THRESH + Calib3d.CALIB_CB_FILTER_QUADS);
if (found) {
determineHomography();
}
确定单应性的代码：
Point[] data = imageCorners.toArray();
if (data.length < chessboardSize.area()) {
return;
}
Point[] roi = new Point[] {
data[0 * (int)chessboardSize.width - 0], // Top left
data[1 * (int)chessboardSize.width - 1], // Top right
data[((int)chessboardSize.height - 1) * (int)chessboardSize.width - 0], // Bottom left
data[((int)chessboardSize.height - 0) * (int)chessboardSize.width - 1], // Bottom right
};
Point[] roo = new Point[] {
new Point(0, 0),
new Point(viewSize.width, 0),
new Point(0, viewSize.height),
new Point(viewSize.width, viewSize.height)
};
MatOfPoint2f objectPoints = new MatOfPoint2f(), imagePoints = new MatOfPoint2f();
objectPoints.fromArray(roo);
imagePoints.fromArray(roi);
Mat H = Imgproc.getPerspectiveTransform(imagePoints, objectPoints);
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