如何打破JavaScript中的嵌套循环？

Question

我尝试了这个：

for(i = 0; i < 5; i++){

    for(j = i + 1; j < 5; j++){

        break(2);

    }

    alert(1);

}

只能得到：

SyntaxError：;声明前缺失

那么，我该如何打破JavaScript中的嵌套循环？

Answer 1

您应该能够打破标签，就像这样：function foo (){&nbsp; &nbsp; dance:&nbsp; &nbsp; for(var k = 0; k < 4; k++){&nbsp; &nbsp; &nbsp; &nbsp; for(var m = 0; m < 4; m++){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; if(m == 2){&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; break dance;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }}

Answer 2

loop1:&nbsp; &nbsp; for (var i in set1) {loop2:&nbsp; &nbsp; &nbsp; &nbsp; for (var j in set2) {loop3:&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; for (var k in set3) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; break loop2;&nbsp; // breaks out of loop3 and loop2&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }从最佳方式复制的代码打破Java嵌套循环？发表问题前请先搜索。链接是我在本页左侧看到的第一个相关问题！