检查变量的多个值

Question

original = raw_input('Enter a word:')

if len(original) > 0 and original.isalpha():

    word = original.lower()

    first = str(word)[0]

    print first

    if str(first) == "a" or "e" or "i" or "u" or "o":

        print "vowel"

else:

    print "consonant"

我想检查一个单词是否以元音或辅音开头。但是，这部分不起作用：如果str(first) == "a" or "e" or "i" or "u" or "o"

那么你如何检查第一个字母是“a”还是“e”或“i”或“u”还是“o”？

Answer 1

你最好用 in    if len(original) and original.isalpha():        word = original.lower()        first = word[0]        print first        if first in ('a','e','i','o','u'):            print "vowel"        else:            print "consonant"你也做错了，如果你试图使用OR子句你必须使用这样但是它不是更好的pythonic方式： if first =='a' or first =='e' or first =='i' or first =='o' or first =='u':

Answer 2

if str(first) == "a" or "e" or "i" or "u" or "o":应该修改为if str(first) in ("a", "e", "i", "o", "u"):Python对缩进有明确的要求。确保你有一个正确的缩进。original = raw_input('Enter a word:')if len(original) > 0 and original.isalpha():    word = original.lower()    first = str(word)[0]    print first    if str(first) in ("a", "e", "i", "o", "u"):        print "vowel"    else:        print "consonant"