如何将一个巨大的整数（字符串格式）转换为十六进制格式？（C＃）

Question

给定一个潜在的巨大整数值（采用C＃字符串格式），我希望能够生成其十六进制等效值。普通方法在这里不适用，因为我们正在谈论任意大数，50位或更多。我见过的技术使用了这样的技术：

// Store integer 182

int decValue = 182;

// Convert integer 182 as a hex in a string variable

string hexValue = decValue.ToString("X");

// Convert the hex string back to the number

int decAgain = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);

将无法工作，因为要转换的整数太大。

例如，我需要能够像这样转换字符串：

843370923007003347112437570992242323

到十六进制当量。

Answer 1

哦，这很简单：&nbsp; &nbsp; &nbsp; &nbsp; var s = "843370923007003347112437570992242323";&nbsp; &nbsp; &nbsp; &nbsp; var result = new List<byte>();&nbsp; &nbsp; &nbsp; &nbsp; result.Add( 0 );&nbsp; &nbsp; &nbsp; &nbsp; foreach ( char c in s )&nbsp; &nbsp; &nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; int val = (int)( c - '0' );&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; for ( int i = 0 ; i < result.Count ; i++ )&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; int digit = result[i] * 10 + val;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; result[i] = (byte)( digit & 0x0F );&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; val = digit >> 4;&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; if ( val != 0 )&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; result.Add( (byte)val );&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; &nbsp; &nbsp; var hex = "";&nbsp; &nbsp; &nbsp; &nbsp; foreach ( byte b in result )&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; hex = "0123456789ABCDEF"[ b ] + hex;