另一种解决方案是分配RangeIndex或range：df.index = pd.RangeIndex(len(df.index))df.index = range(len(df.index))它更快：df = pd.DataFrame({'a':[8,7], 'c':[2,4]}, index=[7,8])df = pd.concat([df]*10000)print (df.head())In [298]: %timeit df1 = df.reset_index(drop=True)The slowest run took 7.26 times longer than the fastest. This could mean that an intermediate result is being cached.10000 loops, best of 3: 105 µs per loopIn [299]: %timeit df.index = pd.RangeIndex(len(df.index))The slowest run took 15.05 times longer than the fastest. This could mean that an intermediate result is being cached.100000 loops, best of 3: 7.84 µs per loopIn [300]: %timeit df.index = range(len(df.index))The slowest run took 7.10 times longer than the fastest. This could mean that an intermediate result is being cached.100000 loops, best of 3: 14.2 µs per loop