在线等，挺急的！如何用空数组，补齐数组数量十分感谢

Question

test=
[
["qwe","1"],
["ewq","2"],
["aaa","4"],
]
我想让数组数量保持在四个，有缺就补空数组，并且要照数组内的数字去补，却哪里补哪里
补完要像这样
test=
[
["qwe","1"],
["ewq","2"],
["",""],
["aaa","4"],
]
该如何实现这需求?

Answer 1

lettest=[["qwe","1"],["ewq","2"],["aaa","4"],]functionsetArr(test){for(leti=0;i

Answer 2

test.reduce((acc,cur,i)=>{while(cur[1]-1!=i){acc.push(['','']);i++}acc.push(cur);returnacc;},[])前提默认原数组是按循序(1,2,3...)排列的